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3 years ago

The net of a triangular prism is shown below.

Mathematics

2 answers:

ollegr [7]3 years ago

8 0

Answer:

Step-by-step explanation:

perimeter of the base = 4+4+5+5=18

the first box will make up the base of the prism

and perimeter is the sum of the sides of the shape

arsen [322]3 years ago

5 0

Answer:

12 units

Step-by-step explanation:

The base of a triangluar prisim is the triangle. The perimeter is the sum of all three sides of the triangle which are 3, 4, 5

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Find the m GEOMETRY 9th:)

maksim [4K]

Answer:

∠ WOT = 85

Step-by-step explanation:

To find the measure of ∠WOT

we know that ∠UOV is 180 in the pic

so by letting ∠WOT = x

∠UOT + ∠WOT + ∠WOV = 180

30 + x + 65 = 180

95 + x = 180

x = 180-95

x = 85

so ∠ WOT = 85

4 0

2 years ago

A blank can be either addition subtraction division or multiplication

Stels [109]

A blank is usually multiplication because (1)1 means to multiply without any actual symbol, but on the other hand, addition, subtraction nor division will have a blank because their signs are different than multiplication which has many sorts of ways to multiply in any way that makes you comfortable.

5 0

3 years ago

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured parallel to a line

Ber [7]

Answer:

The distance is:

$\displaystyle\frac{3\sqrt{142}}{10}$

Step-by-step explanation:

We re-write the equation of the line in the format:

$\displaystyle\frac{x+2}{3}=\frac{y+\frac{3}{2}}{2}=\frac{z+\frac{4}{3}}{\frac{5}{3}}$

Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.

In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:

$\displaystyle\vec{v}=\left< 3, 2, \frac{5}{3}\right>$

Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:

$x=-2+3t\\y=3+2t\\\displaystyle z=-4+\frac{5}{3}t$

We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:

$\displaystyle x+y+z=3\to -2+3t+3+2t-4+\frac{5}{3}t=3$

Then we solve that equation for t, to get:

$\displaystyle \frac{20}{3}t-3=3\to t=\frac{9}{10}$

Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:

$\displaystyle x=-2+3\left(\frac{9}{10}\right)=\frac{7}{10}\\\displaystyle y=3+2\left(\frac{9}{10}\right)=\frac{24}{5} \\\displaystyle z=-4+\frac{5}{3}\left(\frac{9}{10}\right)=-\frac{5}{2}$