The net of a triangular prism is shown below.
2 answers:
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Answer:
Explanation:
<u>1. Given vector:</u>
- length: 4.00 mm = magnitude of the vector
- angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)
<u>2. y-component</u>
The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.
- sine (23.5º) = y-component / magnitude
- y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.