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ASHA 777 [7]
3 years ago
6

David correctly factored the expression m^2 -12m - 64.

Mathematics
1 answer:
sveticcg [70]3 years ago
4 0

Answer:

(3) (m - 16)(m + 4)

Step-by-step explanation:

Given the expression:

m^2 -12m - 64.

Using quadratic formula:

m = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

m = \frac{12 \pm \sqrt{(-12)^2 - 4(1)(-64)}}{2(1)}

m = \frac{12 \pm 20}{2}

m_1 = \frac{12 + 20}{2}

m_1 = 16

m_2 = \frac{12 - 20}{2}

m_2 = -4

Then, the factored expression is:

(m - 16)(m + 4)

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Question 2 ONLY
Butoxors [25]

In triangle ABC angle c = 180-78-40 = 62 degrees

For the triangles to be congruent angle z must equal angle C

Solve for x:

2x + 8 = 62

Subtract 8 from both sides:

2x = 54

Divide both sides by 2:

X = 27

Now we k ow x has to equal 27 to be concurrent so we can answer the 3 questions.

A. False

B. True

C. True

3 0
3 years ago
What is the value of log27^9?
Dahasolnce [82]

Answer:

12.8822738774

Step-by-step explanation:

this is that answer

5 0
4 years ago
Read 2 more answers
a shopkeeper bought a dress for 750 and sold it ,making a loss of 50 .calculate the percentage loss made on the sale​
kiruha [24]

Answer:

<u><em>He made a loss of 6.67%</em></u>

Step-by-step explanation:

Loss percentage =  \frac{Loss}{Cost price} * 100

Loss = 50

Cost price = 750

Hence, Loss percentage=

\frac{50}{750} *100

=\frac{20}{3} = 6.66 %

He made a loss of 6.6666%.

This amount can be rounded up to 6.67%

<em>Hope this helps.</em>

4 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.05 for the estimation of a population pro
VashaNatasha [74]

Answer:

The sample size 'n' = 384

Step-by-step explanation:

<u>Step(i)</u>:-

Given data the margin of error = 0.05

The margin of error of the estimation of a population proportion is determined by

M.E = \frac{Z_{\frac{\alpha }{2} }\sqrt{p(1-p}  }{\sqrt{n} }

<u><em>Step(ii)</em></u>:-

In data not given sample proportion 'p' but

we know that \sqrt{p(1-p} \leq \frac{1}{2}

0.05 = \frac{1.96 X \frac{1}{2} }{\sqrt{n} }

cross multiplication, we get

0.05 ×√n = 0.98

\sqrt{n} = \frac{0.98}{0.05} = 19.6

<em>squaring on both sides, we get</em>

<em>n = 384.16≅ 384</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The sample size 'n' = 384</em>

7 0
4 years ago
A car traveling east at a constant rate of 33 mi/hr passes through an intersection at 10 A.M. A truck traveling north at a const
Rufina [12.5K]

Answer:52.33 m/s

Step-by-step explanation:

Given

Speed of car v_1=33 mi/hr

Speed of truck v_2=42 mi/hr

Distance traveled by car in 1 hr is 33 mi

Therefore after 11 am distance of car and truck from Junction in time t is  

Car =33+33t

truck =42 t

Let D be the distance between them

D^2=42t^2+(33+33t)^2------------1

at t= 2 hr

D^2=(42\times 2)^2+(33+66)^2

D=129.83 miles

To get how fast distance between them is increasing differentiate 1 we get

2D\frac{\mathrm{d} D}{\mathrm{d} t}=2\cdot(42)^2t+2\cdot 33^2(1+t)

\frac{\mathrm{d} D}{\mathrm{d} t}=\frac{42^2t+33^2\left ( 1+t\right )}{D}

\frac{\mathrm{d} D}{\mathrm{d} t}=\frac{1764\times 2+1089\times 3}{D}

\frac{\mathrm{d} D}{\mathrm{d} t}=\frac{6795}{129.83}=52.33 m/s

3 0
4 years ago
Read 2 more answers
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