Answer:It's the last option again. You have 1 linear factor (3x) and 2 copies of a quadratic factor (x² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.
Step-by-step explanation:
Answer:
The answer to your question is ( -7/10, -4 7/10)
Step-by-step explanation:
Data
Enpoint (3/2, 1 1/2) x1 = 3/2 y1 = 1 1/2
Midpoint (2/5, -8/5) xm = 2/5 ym = -8/5
Entpoint 2 ( x, y)
Formula
Xm = (x1 + x2)/2 Solve for x2 x2 = 2xm - x1
Ym = (y1 + y2)/2 Solve for y2 y2 = 2ym - y1
Substitution
x2 = 2(2/5) - 3/2
x2 = 4/5 - 3/2
x2 = (8 - 15)/10
x2 = -7/10
y2 = 2(-8/5) - 1 1/2
y2 = -16/5 - 3/2
y2 = (-32 - 15) / 10
y2 = -47/10 = -4 7/10
g(x)= 3k-2x²
g(-3)=-6 ____(1)
So, using (1),
-6 = g(-3)
=> -6 = 3k - 2(-3)²
=> -6 = 3k - 2(9)
=> -6 = 3k - 18
=> -6 +18 = 3k
=> 12 = 3k
=> 12/3 = k
=> 4 = k
Now, you can find g(n) for any number n, as now we know the value of k. Specify the value of x, if you want to know what is g(x).
Answer:
9/14
Step-by-step explanation:
3/7 ÷ 2/3=
3/7 × 3/2=
3×3 / 7×2=
9/14
Hope this helps!