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kifflom [539]
2 years ago
15

Tell whether the equation has one, zero, or infinitely many solutions 8(x – 5) + 36 = 7x – 2​

Mathematics
2 answers:
swat322 years ago
8 0
It has one solution, x=2
ddd [48]2 years ago
8 0

Answer:

jroteejktrsafh‍❤️♥️❣️❣️♥️♥️‍‍‍‍‍‍‍‍☘️

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HEEEEELP ASAP!!!!! I need this to graduate!!!!!!!
yanalaym [24]

The answer is y=\frac{2}{3} x+7

4 0
2 years ago
Read 2 more answers
the 6:00 a.m. temperatures for four consecutive days in the town of Lincoln were -12.1 C, -7.8 C, -14.3 C and -7.2 C what was th
Marrrta [24]

Answer:

-10.4

Step-by-step explanation:

You add all of the temperatures together and then divide the total by 4 (because there are four temperatures) and you get 10.35. You round that up to 10.4

3 0
2 years ago
Please help me with this question
MariettaO [177]

Answer:

It would be A,B

Step-by-step explanation:

3 0
3 years ago
What type of covalent bond diagram only shows the outer shell of electrons?
vitfil [10]
Correct answer: <span>Dot-and-cross-diagram
</span>

Dot-and-cross diagrams are used to represent covalent bonds. The shared electron from one atom is shown as a dot, while the shared electron from the other atom is shown as a cross.

When drawing dot-and-cross diagrams for covalent bonds, you only need to show the electrons in the highest occupied energy level, as only these are involved.

4 0
3 years ago
A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
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