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mario62 [17]
3 years ago
14

12. Write the equation of the line passing through the point (2,6) with slope 4 in

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

y = 4x - 2

Step-by-step explanation:

slope = 4

y -6 = 4 ( x- 2 )

distribute the 4 to ( x - 2 )

y - 6 = 4x - 8

add 6 to both side

y = 4x - 2

Hopefully this helps you understand this concept.

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Rewrite 7 − 8 using the additive inverse
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Answer:

-8 + 7

Step-by-step explanation:

7 - 8 = -1

-8 + 7 = -1

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What is 0.7, 7/9, 7/8 in order from greatest to least
Sphinxa [80]
Simple...

change them all into fractions or decimals...

0.7---> 0.7

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3 years ago
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3 years ago
Fine the equation of the line that is perpendicular to the given line and passes through the given point. Enter the right side o
Kipish [7]

Answer:

y=-\frac{4}{7} x+\frac{55}{7}

Step-by-step explanation:

Change the given equation to slope-intercept to get y=\frac{7}{4}x-\frac{1}{4}. When you multiply the slopes of perpendicular lines, you get -1. -1 divided by \frac{7}{4} is -\frac{4}{7}. The slope of the new line is then -\frac{4}{7}. The perpendicular line passes through (5, 5) so you can have the equation5=-\frac{4}{7} (5)+b. Simplifying gets b = \frac{55}{7} . So now the final equation for the perpendicular line is y=-\frac{4}{7} x+\frac{55}{7}

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