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2 years ago

15

Identify the quadrant or axis that the following point lies on. If the point lies on an axis, specify which part (positive or ne

gative) of which axis (x ory).
(-2,-5)

1 answer:

IgorC [24]2 years ago

6 0

Answer:

Quadrant 3! Hope this helps!

Step-by-step explanation:

The x and y are both negative. Meaning that they will lie on quadrant 3 which both axis in this quadrant are negative.

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Proving the Converse of the Parallelogram Side Theorem

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Step-by-step explanation:

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3 years ago

Read 2 more answers

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

1c

$n = 33$

1d

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$

=> $P( X \ge 1) = 1 - P( X =0 ) > 0.95$

=> $P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95$

=> $1 - [1 * 1* (0.85)^{n}] > 0.95$

=> $[(0.85)^{n}] > 0.05$

taking natural log of both sides

$n = \frac{ln(0.05)}{ln(0.85)}$

=> $n = 19$

3 0

2 years ago

Vanyuwa [196]

Answer:

a = 19

Step-by-step explanation:

If the rate of change is -8, subtract 8 from your y value of 27. And if 19 is correct, you should be able to subtract 8, and get 11 as the next number in the function, which you do, so 19 is the value of a.

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2 years ago