Answer:
I believe the answer is Euryhaline
C) It makes the overall crop more susceptible to pests or disease. is the correct answer
Answer:
A. donation of excited electrons by chlorophyll a to a primary electron acceptor
Explanation:
Photosystems are structures located at the thylakoid membrane that act to harvest energy light in order to convert it into chemical energy. Each photosystem is composed of a light-harvesting complex and a core complex, which in turn is composed of a reaction center. The photosynthetic reaction centers are multi-protein complexes that use light energy to catalyze the electron transfer across the chloroplast thylakoid membrane against a thermodynamic gradient. Moreover, antenna pigments are pigments that capture the energy from photons in order to transfer energy to other pigments in the photosystem (e.g., chlorophyll B and carotenes are antenna pigments, whereas chlorophyll A is the core pigment). Light energy absorbed by antenna pigments in the photosystems is transferred to the reaction center chlorophyll A molecules, thereby exiting electrons in the reaction center. A reaction center consists of two chlorophyll A molecules, which donate electrons to the primary electron acceptor.
0.1 M solution of a disaccharide solution will contain 2000 monosaccharide molecules.
<h3>What are monosaccharides?</h3>
Monosaccharides, also known as simple sugars are the simplest monomers of carbohydrates which may either be 3 carbon, 4 carbon, 5 carbon, 6 carbon or 7 carbo compounds.
There are two types of monosaccharides;
- aldoses sugars, e.g. glucose, and
- ketose sugars e.g. fructose.
When two monosaccharides are linked together by glycosidic bonds to form a single compound, the compound formed is called a disaccharide.
Considering the give question:
Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide molecules. How many monosaccharide molecules would be in a 0.1 M solution of a disaccharide.
The number of monosaccharides molecules present in the 0.1 M solution of a disaccharide is determined as follows:
1 disaccharide molecule contains 2 monosaccharide molecules
0.1M solution of a monosaccharide contains 1000 monosaccharide molecules.
0.1 M solution of a disaccharide will contain 2 * 1000 monosaccharide molecules
0.1 M solution of a disaccharide will contain = 2000 monosaccharide molecules.
Learn more about monosaccharides and disaccharides at: brainly.com/question/731310
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