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3 years ago

Which of the following equations are linear? (choose all that apply)

Mathematics

1 answer:

lions [1.4K]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

yes y = 2x + 1

yes 5x = 6 + 3y

yes y/2 = 3 − x

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the volume of a cube is 64in squared (2). what’s the length of each side of the cube please help asap

blsea [12.9K]

Answer:

4in squared

Step-by-step explanation:

We know that cubes have equal parts all around, and it is basic knowledge for the most part to know 4x4x4 = 64. Therefore, each length must be 4, length, width,and height are all 4.

8 0

2 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Jack biked to his friend house at a speed of 10 mph. When he was returning home it was raining. So he biked much slower - at 6 m

AVprozaik [17]

Answer:

7.5

Step-by-step explanation:

The relation between time, speed, and distance is ...

time = distance/speed

If distance is "1 round trip", then the time going is ...

going = 0.5/(10 mi/h) . . . . for 1/2 round trip

and the time coming is ...

coming = 0.5/(6 mi/h)

Then the average speed for the full round trip is ...

speed = distance/time

average speed = 1/(going + coming) = 1/(0.5/10 +0.5/6) mi/h

= 1/((3+5)/60) mi/h

= 60/8 mi/h = 7.5 mi/h

Jack's average speed for the round trip was 7.5 mph.

7 0

3 years ago

Hi, I need the area to this problem i need the answer and to show my work no hackers please

Harrizon [31]

28 yards is the answer

4 0

2 years ago

Factor completely: 4x2 + 25x + 6

IceJOKER [234]

(x + 6)(4x + 1)
x times 4x = 4x^2
x times 1 = x
6 times 4x = 24x
6 times 1 = 6
And finally, by adding like terms, 4x^2 + 25x + 6

I hope this helps you! Good luck :)

7 0

3 years ago