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klemol [59]
3 years ago
6

Complete the parts to match Photo uploaded I need help with the second one?

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0
7/20 , 0.35 & 35%
hope this helps :.)
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If A = (7,9) and B = (3 , 12) what is the length of AB
V125BC [204]

Answer:

AB = 5 units

Step-by-step explanation:

Calculate the length using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+ (y_{2}-y_{1})^2

with (x₁, y₁ ) = A(7, 9) and (x₂, y₂ ) = B(3, 12)

AB = \sqrt{(3-7)^2+(12-9)^2}

      = \sqrt{(-4)^2+3^2}

      = \sqrt{16+9}

      = \sqrt{25}

       = 5

7 0
2 years ago
Solve this linear equation: <br><br>x/2 + 3/4 = x/8 ​
horsena [70]
8 * (x/2 + 3/4 ) = 8 * ( x/8 )

Number of solutions found: 1
x1=-2
5 0
2 years ago
A house purchased for $230,000 has lost 6% of its value each year for the last four years. What is the house worth now?
lutik1710 [3]
You can use the compound growth to work this out,

Firstly you need to make a multiplier for -6%;
1-(6/100) = 0.94

The you times the amount of money by 0.94 to the power of 4 because you are working out 4 years:
230000*0.94^4 = 179527.26

The answer is $179527.26,
Hope this helps! :)
3 0
3 years ago
Find the HCF and LCM of 4x^2 - 36 ,2x^2 - 12x + 18 and 2x^2 + x - 21​
olga_2 [115]

Answer:

(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)

Step-by-step explanation:

Factor all the expressions,

1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)

2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)

3rd expression=2x^2 + x - 21​=(x - 3) (2 x + 7)

HCF=Commo factor=(x-3)

LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)

4 0
3 years ago
Will Give Brainliest! Evaluate (2 - 3)^4(4) - 9 ÷ 3.<br> -7<br> -2<br> 1<br> 2
Karo-lina-s [1.5K]

(2 - 3)^4(4) - 9 ÷ 3

(-1)^4(4)-9/3

1(4)-9/3

4-3

answer: 1

8 0
3 years ago
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