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3 years ago

14

Check to see the given number is a solution of the equation or inequality x+9=17;8

1 answer:

timofeeve [1]3 years ago

6 0

Yes, 8 is a solution to the equation

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BRAINLIEST Look at the pattern and decide what number comes next.<br> 2 7 3 8 4 9 5 ?

baherus [9]

Answer:

10

Step-by-step explanation:

2 + 5 = 7

3 + 5 = 8

4 + 5 = 9

5 + 5 = 10

4 0

2 years ago

Read 2 more answers

Express the measurement 4.29478416 kg with 8, 6, 4, and 2 significant figures

ira [324]

Significant figures refers to digits within a number which must be included in other depict correct quantity of the figure.

4.29478416 = 4.2947842 ( 8 significant figures)
4.29478416 = 4.29478 (6 significant figures)
4.29478416 = 4.295 ( 4 significant figures)
4.29478416 = 4.3 (2 significant figures)

To round a number to a certain number of significant figures,

Only leading 0 which comes before the decimal Point are regarded as insignificant.
Once the number of significant figures have been identified, the next number after this is either rounded up to 1 and added to the last value(if number is ≥5) or rounded to 0 (if number is less than 5)

Learn. More : brainly.com/question/13386983?referrer=searchResults

3 0

2 years ago

F(x) = 2x2 - 4x?; Find (-4)

anastassius [24]

Answer:

0 (zero)

Step-by-step explanation:

Plug in the variable for -4 and solve

y= 2(-4)2-4(-4)

y= -8(2)-4(-4)

y=-16+16

y=0

4 0

2 years ago

Find the volume of the composite solid. Round your answer to the nearest tenth.

amm1812

Answer:

Volume of the Figure $=825.38m^3$

Step-by-step explanation:

Volume of the figure = Volume of the Upper cone+Volume of the lower cone

Volume of a cone = $\pi *r^2*\frac{h}{3}$

Volume of the Upper Cone with

$height=12m$

$radius=6m$

$3.14*6*6*\frac{12}{3}$

$=3.14*6*6*4\\\\=3.14*36*4\\\\=3.14*144\\\\=147.14m^3$

Volume of the Lower cone with $radius=6m$ and $height=18m$

$=3.14*6*6*\frac{18}{3} \\\\=3.14*6*6*6\\\\=3.14*36*6\\\\=3.14*216\\\\=678.24m^3$

Volume of the Whole Figure = $147.14+678.24$

Volume of the Figure $=825.38m^3$

4 0

2 years ago

Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho

Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

$A_{g} = a.b$

<u>Where:</u>

Ag: is the area of the rectangular garden

a: is the length of the rectangular garden = 50 cm = 0.5 m

b: is the width of the rectangular garden = 34 m

$A_{s} = 540 m^{2}$

<u>Where</u>:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

$A_{s} + A_{g} = (a+2x)*(b+2x)$

$540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}$

$557 m^{2} = ab + 2x(a + b) + 4x^{2}$

$557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0$

$540 - 69x - 4x^{2} = 0$

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

7 0

3 years ago