H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
Answer:
6 Cut Minimum
Step-by-step explanation:
According to the Question,
You have a 3x3x3 cube.
- First make two cuts parallel to base of the cube each at a distance of 1 unit . This leaves you with three cuboids of dimensions 3x3x1.
- Now make two parallel cuts parallel to the height of the cube. This leaves you with nine cuboids of dimensions 3x1x1.
- Now make the final two cuts each 1 unit apart parallel to width and you are left with 27 cubes of 1x1x1.
So , the final answer is 6 cuts.
B=6 i believe! if you use the pythagorean theorem (a^2+b^2=c^2) then you should be able to turn 8^2 and 10^2 into 64 and 100, respectively. 100-64=36 and the square root of 36 is 6. you can plug it in by calculating 8^2 + 6^2, which equals 100! hope this wasn't too confusing XD
Positive. 125/5 = 125 divided by 5 which equals 25.
