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a_sh-v [17]
3 years ago
9

The measure of one angle is six more than half the measure of another angle. If the angles are complementary, find both measures

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

The measures of the two angles are 34° and 56°

Step-by-step explanation:

* Lets explain how to solve the problem

- The complementary angles are the angles whose the sum

  of their measures is 90°

- The measure of one angle is six more than half the measure

 of another angle

- Let the measure of the second angle angle is x

∵ The measure of the 2nd angle is x

∵ The measure of the first angle is 6 more than the half of the

  measure of the second angle

∴ The 1st angle is 6 + 1/2 x

∵ The two angles are complementary

∴ The sum of their measures is 90°

∴ x + (6 + 1/2 x) = 90

∴ (x + 1/2 x) + 6 = 90

∴ 3/2 x + 6 = 90

- Subtract 6 from both sides

∴ 3/2 x = 84

- Multiply both sides by

∴ 3x = 168

- Divide both sides by 3

∴ x = 56

∵ x is the measure of the 2nd angle

∴ The measure of the 2nd angle is 56°

∵ The measure of the 1st angle = 6 + 1/2 x

∵ x = 56

∴ The measure of the 1st angle = 6 + 1/2(56) = 34°

* The measures of the two angles are 34° and 56°

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Answer:

189

Step-by-step explanation:

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3 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

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P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
BRAINLIEST HELP MEEE<br> 7x + 3 = 2x + 13
lianna [129]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Two train stations are 50 miles apart. At noon, a train starts out from each station heading for each other. Just as they pull o
Daniel [21]

Answer: 100 miles

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3 0
4 years ago
Totsakan school is selling tickets to a choral performance on the first day of ticket sales the school sold 10 senior tickets an
ohaa [14]

Given :

On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .

The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.

To Find :

The price of a senior ticket and the price of a child ticket.

Solution :

Let, price of senior ticket and child ticket is x and y respectively.

Mathematical equation of condition 1 :

10x + y = 85    ...1)

Mathematical equation of condition 2 :

5x + 7y = 75    ...2)

Solving equation 1 and 2, we get :

2(2) - (1)   :

2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0

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x = 8

Therefore, price of a senior ticket and the price of a child ticket $8 and $5.

Hence, this is the required solution.

 

5 0
3 years ago
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