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Vlada [557]
3 years ago
14

Explain how you can find 3×584 using expanded form

Mathematics
2 answers:
ololo11 [35]3 years ago
6 0
3 x 500 
+
3 x 80
+
3 x 4 
=
1,752

By expanding 584 and multiplying the different parts by 3, the multiplying is simplified. Then you just have to add together the multiplication you did.
alex41 [277]3 years ago
6 0
Hello Starrlynuoxz14o, first you multiply 3 x 500, then multiply 3 x 80, after that multiply 3 x 4. Then add all the answers you got.
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Write the equation and<br> solve for x.<br> (4n+22) (8n-10)
Sati [7]

Answer:

32n^{2} + 136n − 220

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8 0
3 years ago
Fidn the points of intersection
Sedbober [7]

EQ. 1: x + y = 8

EQ. 2: 4x-y = 7

Rewrite EQ. 1 as EQ. 3: x = 8-y

Replace x in EQ.2 with EQ. 3:

4(8-y) - y = 7

Use the distributive property:

32 - 4y - y = 7

Combine like terms:

32 - 5y = 7

Subtract 32 from each side:

-5y = -25

Divide both sides by -5

y = -25 / -5

y = 5


Now replace y with 5 in EQ. 3 to solve for X:


x = 8-5

x = 3


The point of intersection is X = 3, Y = 5, which is written as (3,5)

8 0
3 years ago
HELP PLEASE..........
serg [7]

Answer:

19.47

Step-by-step explanation:

Use the law of sines.

sin(90)/6 = sin(x)/2

Multiply both sides by 2

2 * sin(90)/6 = sin(x)

Use a calculator

0.33333 = sin(x)

sin^-1 0.3333 = 19.47

5 0
2 years ago
Write the standard form of the equation of the circle that passes through the point
AnnZ [28]

Answer:

The standard form of the equation of the circle is x^2+y^2=1.

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

                                             (x-h)^2+(y-k)^2=r^2

where <em>r</em> is the radius of the circle,  and <em>h</em>, <em>k</em> are the coordinates of its center.

When the center of the circle coincides with the origin h=k=0, so

                                            (x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2

We are also told that the circle contains the point  (0, 1), so we will use that information to find the radius <em>r</em>.

                                                   0^2+1^2=r^2\\r^2=0^2+1^2\\r^2=1\\r=\sqrt{1}

Therefore, the standard form of the equation of the circle is x^2+y^2=1.

5 0
3 years ago
Use the substitution method
vitfil [10]

Answer:

z = 9

z = 2

z = 5

z = 8

z = 11

Step-by-step explanation:

5 0
3 years ago
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