Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.
The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as:
Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s = 154.9 mol/L
Consider the Chemical Reaction first:
Reaction: H₂SO₄ + 2 NaCl → 2 HCl + Na₂SO₄
Now, Given mass of NaCl = 30 g
Molar mass of Nacl = 58 g/mol
Now, Number of moles of NaCl = 30/58 = 0.517 mol
Balance the equation, For every 2 molecules of NaCl, 2 molecules of HCl formed, so the number of moles would be same.
Hence, Number of moles of HCl = 0.517 mol
Now, Mass of HCl = Molar mass of HCl * Number of moles
Mass = 36 * 0.517 [ Molar mass of HCl = 36 ]
Mass = 18.62 g
In short, Your Answer would be: 18.62 Grams
Hope this helps!
<em>C = 0,75 mol/dm³</em>
<em>V = 500mL = 500cm³ = 0,5dm³</em>
C = n/V
n = 0,75×0,5dm³
<u>n = 0,375 moles</u>
<em>M NaCl: 23+35,5 = 58,5g</em>
1 mole ---------- 58,5g
0,375 ----------- X
X = 0,375×58,5
<u>X = 21,9375g NaCl</u>
:)
Answer:
a. are isomers of each other
b. have same molecular formula
d. are both hydrocarbons
e. have same number of each kind of atom
Explanation:
hope this helps!
