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Marianna [84]
3 years ago
10

With the intensity at about half of maximum, how does the current change when you increase the frequency of the light?

Physics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

Increase

Explanation:

Energy  of  given as follows

E = h f

Where f is the frequency of incident light

when high frequency light falls then it will increase the number of produce photon and that increase in number of photon will lead to increase in the number of electron.When number of electron will increase it mean that current will also increase.

So we can say that when frequency increase then current will increase.

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Need help really fast ! can give brainliest if correct :> thanks <3
Vlada [557]

Answer:

2. Move faster

Explanation:

Because you lighten the weight and pushed at the same speed it is easier to push the 400-grams than the 800-grams.

Have a wonderful day!

8 0
3 years ago
Read 2 more answers
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
ra1l [238]

Answer:

a) t = 4.16 s

b) x = 141.51 m

Explanation:

Given

v = 21.5 m/s

x0 = 52.0 m

a = 6.0 m/s²

a) Motorcycle

x = v0*t + (a*t²/2)

x = 21.5t + (6*t²/2)

x = 21.5t + 3t²   <em>(I)</em>

Car

x = x0 + v0*t

x = 52 + 21.5t  <em>(II)</em>

<em />

then we can apply <em>I = II</em>

21.5t + 3t² = 52 + 21.5t

⇒ 3t² = 52

⇒ t = 4.16 s

b) We can use <em>I</em> or <em>II</em>, then

x = 52 + 21.5*(4.16)

⇒ x = 141.51 m

8 0
3 years ago
A commuter backs her car out of her garage with an acceleration of 1.40 m/s2.A) How long does it take her to reach a speed of 2.
AURORKA [14]

Answer:

(A) 1.43secs

(B) -2.50m/s^2

Explanation:

A commuter backs her car out of her garage with an acceleration of 1.40m/s^2

(A) When the speed is 2.00m/s then, the time can be calculated as follows

t= Vf-Vo/a

The values given are a= 1.40m/s^2 , Vf= 2.00m/s, Vo= 0

= 2.00-0/1.40

= 2.00/1.40

= 1.43secs

(B) The deceleration when the time is 0.800secs can be calculated as follows

a= Vf-Vo/t

= 0-2.00/0.800

= -2.00/0.800

= -2.50m/s^2

4 0
3 years ago
nvestigations were carried out in a science lab to explore the topic of chemical and physical changes. Investigation A Step 1. A
MAVERICK [17]

B Step 1. Mix 10 tsp. white sugar into 100 ml water and stir until most or all of the sugar is no longer visible.

7 0
3 years ago
An electron is projected with an initial speed v0 = 1.10 x 10⁶ m/s into the uniform field between the parallel plates. The dista
ArbitrLikvidat [17]

Answer:

a) E=364N/C

b) No

Explanation:

A) Because the electron is affected by an acceleration force in this case by the electric field, we can use the formulas of 2-dimension movement.

We will assume the electron missed the upper plate, so we need to calculate the time to travel all the way through the plate, that is:

x=v_x*t

where:\\x=distance\\v=speed\\t=time

so:

t=\frac{x}{v_x}=\frac{0.02m}{1.6\cdot 10^6m/s}\\\\t=1.25\cdot10^{-8}

the electron experiences an accelerated motion in the vertical direction, so we can obtain the acceleration of the electron:

y=\frac{1}{2}.a.t^2\\\\where:\\y=vertical\_distance\\a=acceleration\\t=time

so:

a=\frac{2.y}{t^2}\\\\a=\frac{2*(\frac{0.01}{2}m)}{(1.25\cdot10^{-8}s)^2}\\\\a=6.4\cdot10^{13} m/s^2

now we can use the relation:

F=m.a=E.q\\so\\E=\frac{m.a}{q}

where:\\\\E=electric\_field\\m=electron\_mass=9.1\cdot10^{-31}kg\\q=Charge=1.6\cdot10^{-19}\\a=acceleration

Now we can calculate the electric field:

E=\frac{9.1\cdot10^{-31}kg\cdot6.4\cdot10^{13}m/s^2}{1.6\cdot10^{-19}C}\\\\E=364N/C

B) Because the proton has the same charge but positive it will go in the opposite direction, so because we assume the electron didn't touch the plate, the proton won't.

5 0
3 years ago
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