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vladimir1956 [14]
3 years ago
7

Can I PLEASE get some help? I REALLY need it!

Physics
1 answer:
soldi70 [24.7K]3 years ago
7 0
The answer is C. Hope this helps.
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A towrope is used to pull a 1750-kg car, giving it an acceleration of +1.35 m/s ^2. What force does the rope exert?
Klio2033 [76]
Newton's 2nd law of motion:

               Force  =  (mass) x (acceleration)

                           =  (1,750 kg) x (1.35 m/s²)

                           =      2,362.5 Newtons

                              (about 531 pounds)
6 0
3 years ago
Read 2 more answers
A ship maneuvers to within 2.50 x 10^3 m of an islands 1.80 x 10^3 m high mountain peak and fires a projectile at an enemy ship
Neporo4naja [7]

Answer:

Explanation:

Distance between ship and enemy ship

= 500 + 610

= 3110 m

Range of projectile

R = u² sin2θ / g

= (250x 250 sin 150) / 9.8

= 3188m

The projectile falls within a distance of 3188 - 3110 = 78 m from enemy ship

Height of mountain = 1800 m

We shall find the height of projectile when its horizontal displacement is 2500m

x = 2500 , y = ?

u = 2500 ,

y = x / cos θ - .5 g x² /u²cos² θ

\frac{2500}{.2588} - \frac{.5 \times9.8\times2500\times2500}{250\times250\times.2588}

9660 - 7315 m

= 2345 m

It is within 545 m from mountain peak .

8 0
3 years ago
Two steamrollers begin 105 mm apart and head toward each other, each at a constant speed of 1.20 m/s. At the same instant, a fly
levacccp [35]

Answer: 109.4 mm

Explanation: <u>Distance</u> is a scalar quantity and it is the measure of how much path there are between two locations. It can be calculated as the product of velocity and time:  d = vt

The separation between the two steamrollers is 105 mm or 0.105 m. They collide to each other at the middle of the separation:

location of collision = \frac{0.105}{2} = 0.0525 m

To reach that point, both steamrollers will have spent

v=\frac{\Delta x}{t}

t=\frac{\Delta x}{v}

t=\frac{0.0525}{1.2}

t = 0.04375 s

The fly is travelling with speed of 2.5 m/s. So, at t = 0.04375 s:

d = 2.5*0.04375

d = 0.109375 m

Until it is crushed, the fly will have traveled 109.4 mm.

4 0
3 years ago
If a dog is running at 4.38 m/s for 37.34 seconds, how far will it go?
sdas [7]

Answer:

163.5m

this is how far the doggo would go

(In theory)

If I'm wrong I apologize

7 0
3 years ago
A rocket ship in space is at rest relative to a rock floating in deep space. The
Lesechka [4]
So the equation used in this problem is ΔX=V0*T+1/2AT^2 the X is the distance, v0 is initial velocity, T is time, and a is acceleration. So when we plug these values it we get: 108= 0•T+1/2•3•T^2,the 0•t disappears, and the 1/2•3 gets us 1.5, so we have 108=1.5T^2, then we divide 108 by 1.5 which gets us 72=t^2, and we then take the square root and get 8.49=T so the answer is 8.49 seconds.
5 0
3 years ago
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