I have three problems with this question.
#1). If you copied the question exactly the way it's written,
then the question is written very badly. The wording is
misleading, and the more you try to think about it and
puzzle it out, the more it'll damage your understanding
of Physics.
There is no relationship between the force exerted on an
elevator and the distance the elevator is lifted.
-- If the force is anything more than the weight of the elevator ...
even one ounce more ... then it'll lift the elevator as high as
you want.
-- If the force is anything less than the weight of the elevator ...
even one ounce less, then that elevator is headed for the bottom.
#2). You didn't post any graph below, so if we need the graph
to answer the question, then we can't answer the question.
#3). I guess that's OK, because you didn't ask any question.
Answer:
3- A ball of mass 0,50 kg falls and hits the floor at 10m/s,
It rebounds at speed 8.0 m/s, as shown.
before collision
after collision
10 m/s
8 m/s
The collision between the ball and the floor lasts for 0.50 s.
What is the average force acting on the ball during the collision?
<span>Energy is unable to change forms. please select the best answer from the choices provided</span>
F - False
Answer:
0.19
Explanation:
mass of block, m = 40 kg
F = 150 N
Angle make with the horizontal, θ = 60 degree
Let μ be the coefficient of kinetic friction
The component of force along horizontal direction is F Cos θ
= 150 cos 60 = 75 N
As it is moving with constant velocity it mean the acceleration of the block is zero.
Applied force in horizontal direction = friction force
75 = μ x Normal reaction
75 = μ x m x g
75 = μ x 40 x 9.8
μ = 0.19
Thus, the coefficient of kinetic friction is 0.19.
