Answer:
Pressure = 9.94 x 10⁶ Pascals
Explanation:
given data
mass = 51 kg
radius = 0.400 cm
solution
we know Pressure that is express as here
Pressure = total force on an area ÷ the area of the area .................1
and
Force is the woman's weight so weight will be
Weight = mass × gravity .................2
put here value
Weight = 51 × 9.8 m/s²
Weight = 499.8 Newtons
and
Area of a circle of bottom of the heel = (π) × (radius)² ...................3
put here value
Area = (π) × (0.40 cm)²
Area = 0.502654 cm²
Area = 0.0000502654 m²
and
now we put value in equation 1 we get
Pressure = force ÷ area
Pressure = 499.8 ÷ 0.0000502654
Pressure = 9943221.381 N/m²
Pressure = 9.94 x 10⁶ Pascals
Answer
given,
mass of ball = 5.93 kg
length of the string = 2.35 m
revolve with velocity of 4.75 m/s
acceleration due to gravity = 9.81 m/s²
T cos θ = mg
T cos θ = ![5.93\times 9.81](https://tex.z-dn.net/?f=5.93%5Ctimes%209.81)
T cos θ = 58.17
![T sin \theta =\dfrac{mv^2}{r}](https://tex.z-dn.net/?f=T%20sin%20%5Ctheta%20%3D%5Cdfrac%7Bmv%5E2%7D%7Br%7D)
![T sin \theta =\dfrac{5.93\times 4.75^2}{2.35 sin \theta}](https://tex.z-dn.net/?f=T%20sin%20%5Ctheta%20%3D%5Cdfrac%7B5.93%5Ctimes%204.75%5E2%7D%7B2.35%20sin%20%5Ctheta%7D)
![T sin^2 \theta =56.93](https://tex.z-dn.net/?f=T%20sin%5E2%20%5Ctheta%20%3D56.93)
![sin^2 \theta = 1 - cos^2 \theta](https://tex.z-dn.net/?f=sin%5E2%20%5Ctheta%20%3D%201%20-%20cos%5E2%20%5Ctheta)
![T (1 - cos^2 \theta) =56.93](https://tex.z-dn.net/?f=T%20%281%20-%20cos%5E2%20%5Ctheta%29%20%3D56.93)
![T (1 - (\dfrac{58.17}{T})^2) =56.93](https://tex.z-dn.net/?f=T%20%281%20-%20%28%5Cdfrac%7B58.17%7D%7BT%7D%29%5E2%29%20%3D56.93)
T² - 56.93T - 3383.75 = 0
T = 93.22 N
![cos \theta = \dfrac{58.17}{93.22}](https://tex.z-dn.net/?f=cos%20%5Ctheta%20%3D%20%5Cdfrac%7B58.17%7D%7B93.22%7D)
θ = 51.39°
Answer: Velocity terminal = 0.093m/s
Explanation:
1. We start by evaluating the gap distance between the two cylinders as h = R(sleeve) - R(cylinder)
= (0.0604/2 - 0.06/2)m
= 2×10^-4
Surface are of the cylinder in the drop, which is required in order to evaluate the shearing stress can be expressed as A(cylinder) = π.d.L
= (π×0.06×0.4)m²
= 0.075m²
Since the force of the cylinder's weight is going to balance the shearing force on the walls, we can express the next equation and derive terminal velocity from it.
Shearing stress = u×V.terminal/h = 0.86×V/0.0002
= 4300Vterminal
Therefore, Fw = shearing stress × A
30N = 4300Vterminal × 0.075
V. terminal = 30/4300 m.s
V. terminal = 0.093m/s
Answer:
15 N
Explanation:
According to Newton's third law of motion, to every action, there is an equal and opposite reaction. This reaction is equal in magnitude to the force acting but in an opposite direction.
Now, if the book weighs 15 N, an opposite equal force will be: N = -15 N
But the magnitude of this will be the absolute value which is 15N.
Answer:
it increases the amplitude of the wave as it propagates.
Explanation: