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Gnom [1K]
3 years ago
6

How do you ask someone for help?

Computers and Technology
1 answer:
kakasveta [241]3 years ago
5 0
It all depends what you need from that certain person, like maybe you're failing a class and need help from a friend who is better than you at that class, you could say, "hey look man i'm really struggling in this class. Could you help me?" just be straight up with them. or you could message them
You might be interested in
True or False: Changing a bid package's status to "Closed" removed it from the bidder's Planroom and the bidder will no longer b
Readme [11.4K]

Answer:

True

Explanation:

It's actually true because once a bidding page status changes to closed, it means that the timeframe for bidding has stopped, hence, no bidder will be able to bid again.

7 0
3 years ago
We have an internal webserver, used only for testing purposes, at IP address 5.6.7.8 on our internal corporate network. The pack
lukranit [14]

Answer:

Check the explanation

Explanation:

A packet filter firewall is used as a check point between internal corporate network to the outside internet. It blocks all the inbound traffic from the outside hosts trying to initiate a direct TCP connection to the internal corporate webserver. The network design with firewall is shown in the attached image below:

The figures in the attached image below shows an internal corporate network is protected with a packet filter firewall to minimize the inbound traffic from the external network or an internet. Therefore, the packet filter is used as a check point between the network.

The packet filter blocks all attempts by the outside hosts in order to initiate a direct TCP connection to the internal webserver of the internal corporate network.

Going by the second part of the attached image below can can therefore conclude that:

• Rule 1 specifies that, deny any packet with the destination address 5.6.7.8 if the STN flag of TCP header is set.

• Rule 2 specifies that, allow the inbound email traffic from the external source.

• Rule 3 specifies, allows the Outbound TCP traffic from the internal corporate network.

• Rule 4 specifies, allows outbound Email traffic from the internal corporate network to the external network.

• Rule 5 specifies, block any traffic from any source to the any destination.

3 0
3 years ago
Design a class that has an array of floating-point numbers. The constructor should accept an integer argument and dynamically al
attashe74 [19]

Answer:

See explaination for the code

Explanation:

Here is the code

class NumberArray

{

private:

float *aptr; // Pointer to the array

int arraySize; // Holds the array size

float max,min,avg;

public:

NumberArray(int); // Constructor

~NumberArray(); // Destructor

int size() const // Returns the array size

{ return arraySize; }

void storeNumber(float num,int ele);

float retrieveNumber(int ele);

float getHighest();

float getLowest();

float getAverage();

};

//*******************************************************

// Constructor for IntArray class. Sets the size of the *

// array and allocates memory for it. *

//*******************************************************

NumberArray::NumberArray(int s)

{

arraySize = s;

aptr = new float [s];

for (int count = 0; count < arraySize; count++)

*(aptr + count) = 0;

}

//******************************************************

// Destructor for IntArray class. *

//******************************************************

NumberArray::~NumberArray()

{

if (arraySize > 0)

delete [] aptr;

}

void NumberArray::storeNumber(float num,int ele)

{

if(ele<arraySize)

*(aptr+ele)=num;

}

float NumberArray::retrieveNumber(int ele)

{

return *(aptr+ele);

}

float NumberArray::getHighest()

{

float high=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(high<*(aptr+i))

high=*(aptr+i);

return high;

}

float NumberArray::getLowest()

{

float low=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(low>*(aptr+i))

low=*(aptr+i);

return low;

}

float NumberArray:: getAverage()

{

float ag=0;

for(int i=1;i<arraySize;i++)

ag+=*(aptr+i);

ag=ag/arraySize;

return ag;

}

//Header file section

#include <iostream>

using namespace std;

int main()

{

const int SIZE = 10; // Array size

// Define an IntArray with 10 elements.

NumberArray table(SIZE);

//function call to store values

table.storeNumber(1,0);

table.storeNumber(3,1);

table.storeNumber(7,2);

table.storeNumber(2,3);

//display values

cout<<"Highest value:"<<table.getHighest()<<endl;

cout<<"Lowest Value:"<<table.getLowest()<<endl;

cout<<"Average:"<<table.getAverage()<<endl;

///pause system for a while

system("pause");

return 0;

}

6 0
2 years ago
What web 2.0 features allows users to subscribe to a data plan that charges for the amount of time spent on the internet?
galina1969 [7]

Answer:

The answer to this question is given in the explanation section. The correct option is long tail

Explanation:

a.Folksonomy

Folksonomy is a way of organizing data and digital content. With Web 2.0, users can collaboratively manage and tag photos, journals and other media. As more users do this, creates a system of classification for the media and information.  so this option is not correct

b. long tail (correct option)

Some sites are able to offer services as well in which users can subscribe monthly or pay a fee every so often. An example of this would be Netflix.

c.user participation

All users have the free will to contribute to the site which makes many Web 2.0 pages public. With sites such as Wikipedia, anyone is open to the editing of articles. Information is provided two-way instead of solely from the site owner.

d.application

Web 2.0 applications that allow anyone to create and share online information or material they have created. As you know that there are number of different types of web 2.0 applications including wikis, blogs, social networking, folksonomies, podcasting & content hosting services.

3 0
3 years ago
Write the following numbers in binary. 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25
AfilCa [17]
0 1 10 11
Explanaition:
4 0
2 years ago
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