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romanna [79]
3 years ago
7

I know the answers but I don't know how to solve it

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0
You did it right. 1.35 + 7.00 and you have the right answer. is that what you mean?
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Simplify square root of negative 48
77julia77 [94]
\bf \sqrt{-48}\qquad 
\begin{cases}
48=2\cdot 2\cdot 2\cdot 2\cdot 3\\
\qquad 2^2\cdot 2^2\cdot 3\\
\qquad (2^2)^2\cdot 3
\end{cases}\implies \sqrt{-1\cdot (2^2)^2\cdot 3}
\\\\\\
\sqrt{-1}\cdot \sqrt{(2^2)^2\cdot 3}\implies i\cdot 2^2\sqrt{3}\implies 4\sqrt{3}\ i
5 0
3 years ago
An artist is using right triangles in her design. If all the
katovenus [111]
I think it’s C because a triangle is 180 degrees and it’s a right triangle which means there is a 90 degrees angle + 30 degrees.
90+30=120. 180-120=60
Which means the third angle is 60 degrees
3 0
2 years ago
Read 2 more answers
A(r) is a function that gives the area of ta circle with the radius r. It can be written in an equation form as A(r)=3.14r^2. wh
notsponge [240]
A(r)=3.14r^2, when r=5

A(5)=3.14(5^2)

A(5)=3.14(25)

A(5)=78.5 u^2
4 0
3 years ago
Question 7 of 10
Mama L [17]

Answer:

B

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 )

Then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real irrational roots

• If b² - 4ac > 0 and a perfect square then 2 real rational roots

• If b² - 4ac = 0 then 1 real double root

• If b² - 4ac < 0 then 2 complex roots

Given

x² + 3x - 7 = 0 ← in standard form

with a = 1, b = 3, c = - 7 , then

b² - 4ac

= 3² - (4 × 1 × - 7) = 9 + 28 = 37

Since b² - 4ac > 0 then 2 real irrational roots

8 0
3 years ago
Solve this system of equations:<br> -3x + 6y = 9<br> x - 2y = -3
Leokris [45]

Answer:

No solutions

Step-by-step explanation:

no solutions

4 0
3 years ago
Read 2 more answers
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