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ZanzabumX [31]
3 years ago
11

How to solve this problem?

Mathematics
1 answer:
OverLord2011 [107]3 years ago
6 0
What happens when a quadratic function touches the x-axis only once?  It means that the quadratic function has only one real zero.  So which formula should we use? How about the almighty quadratic formula?

So when does the quadratic formula give you only one real zero? When the discriminant is equal to zero!

The discriminant is: b²-4ac

In our quadratic equation that means:
b = (3+m)
a = 4
c = 1

Thus, we need to solve: (3+m)²- 4*(4)*(1) = 0

m²+ 6m + 9 - 16 = 0
m² + 6m - 7 = 0
(m+7)(m-1) = 0
m = -7, 1

That's it! Plug back in and graph to see that it actually works!
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Read 2 more answers
2. Which of the following are terms of the series with nth term T-3n +17? a) 80 b) 170 c)217 d) 312 e) 278 f) 3566
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Answer:

The correct options are a,b,e and f.

Step-by-step explanation:

It is given that the nth terms of the series is defined as

T_n=3n+17

Subtract 17 from both the sides.

T_n-17=3n

Divide both sides by 3.

\frac{T_n-17}{3}=n

The term Tₙ is a term of given series if n is a positive integer.

(a) The given term is 80.

n=\frac{80-17}{3}=21

Since n is a positive integer, therefore 80 is a term of given series.

(b) The given term is 170.

n=\frac{170-17}{3}=51

Since n is a positive integer, therefore 170 is a term of given series.

(c) The given term is 217.

n=\frac{217-17}{3}=66.67

Since n is not a positive integer, therefore 217 is a term of given series.

(d) The given term is 312.

n=\frac{312-17}{3}=98.33

Since n is not a positive integer, therefore 312 is a term of given series.

(e) The given term is 278.

n=\frac{278-17}{3}=87

Since n is a positive integer, therefore 278 is a term of given series.

(f) The given term is 3566.

n=\frac{3566-17}{3}=1183

Since n is a positive integer, therefore 3566 is a term of given series.

Thus, the correct options are a, b, e and f.

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