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miss Akunina [59]
3 years ago
7

When Jose took the test over, he increased his score by 15 percentage points. Jose raised his score to an 83% on the test. Which

of the following equations represents the word problem if "x" represents Jose's score on the first test? x + 15 = 83 x = 15 + 83 x - 15 = 83
Mathematics
2 answers:
JulsSmile [24]3 years ago
5 0
Increased by 15
past score was x
increased by 15 means he raised to 15+x
it was raised to 83%

therefor
x+15=83

first option is right (and first test was 68%)
Marina86 [1]3 years ago
5 0

Answer:

The correct equation is  x+15=83

Option 1 is correct.

Step-by-step explanation:

When Jose took the test over, he increased his score by 15% points

Let he scored in first test x%

In second test scored 83% which was 15% more than first test.

He increased his score by 15% points from first test.

Thus, Scored in second test = x + 15

We are given second test scored 83%

Therefore, x+15 must be equal to 83

Hence, The correct equation is  x+15=83

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Given f(x)=x^2+5 and g(x)=2x^3-1 find (f/g)(-3)
AlekseyPX

For this case we have the following functions:

f (x) = x ^ 2 + 5\\g (x) = 2x ^ 3-1

By definition of composition of functions we have:

(f / g) (x) = \frac {f (x)} {g (x)}

Then substituting:

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Given: m∠EYL=72°<br> Find: mEHL , mLVE
White raven [17]

Answer:

Part 1) The measure of arc EHL is 108\°

Part 2) The measure of angle LVE is 54\°

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

so

m

we have

m

substitute

72\°=\frac{1}{2}(y-x)

144\°=(y-x)

y=144\°+x ------> equation A

Remember that

x+y=360\° -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

x+(144\°+x)=360\°

2x=360\°-144\°

x=216\°/2=108\°

Find the value of y

y=144\°+x

y=144\°+108\°=252\°

therefore

The measure of arc EHL is 108\°

The measure of arc EVL is 252\°

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

m

we have

x=108\°

substitute

m

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