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mario62 [17]
3 years ago
13

Given the parent functions f(x) = log2 (3x − 9) and g(x) = log2 (x − 3), what is f(x) − g(x)?. A. f(x) − g(x) = log2 (2x − 6). B

. f(x) − g(x) = log2 (2x − 12). C. f(x) − g(x) = log2 one third. D. f(x) − g(x) = log2 3
Mathematics
2 answers:
Bezzdna [24]3 years ago
4 0
We are given the two functions:
<span>f(x) = log2 (3x − 9)
</span><span>g(x) = log2 (x − 3)
</span>
Then,
f(x) - g(x) = log2 (3x - 9) - log2 (x - 6) 

Two logarithms of the same bases are subtracted, therefore:
log2 ((3x - 9) / (x - 3))

We factor both the numerator and the denominator by x - 3. This becomes,
log2 ((3)(x - 3) / (x - 3)) 

When further simplified, yields:
log2 (3)
Law Incorporation [45]3 years ago
3 0
F(x) - g(x) = log2 (3x - 9) - log2 (x - 6) 

When two logarithms of the same bases are subtracted they become,
                               log2 ((3x - 9) / (x - 3))
Both the numerator and the denominator can be factored by x - 3. This becomes,
                               log2 ((3)(x - 3) / (x - 3)) 
which simplifies into,
                                      log2 (3).

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How many solutions does the following equation have?
KatRina [158]

Answer:

B

Step-by-step explanation:

-5z +1 = -2z +10

-3z = 9

z=9/-3

Z= -3

7 0
3 years ago
18000lb greater then or less then 9T
Alla [95]
It is equal because every 2000 pounds is 1 ton and 18000lb divided by 2000 equals 9.
5 0
3 years ago
Read 2 more answers
Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
4 years ago
Evaluate 3^-3 x 3^4 x 3 x 3^-5 Answers<br> a. -27<br> b. 1/27<br> c. -81<br> d. 1/81
Sauron [17]
The answer is b. 1/27
3^-3=1/27 and 3^4=81. 1/27×81=3. 3×3=9. 3^-5=1/243. 1/243×9= 1/27. The answer is b. 1/27.
8 0
3 years ago
A grocer wants to make a 10-pound mixture of cash tans peanuts that he can sell for $3.29 per pound. If cashews cost $5.60 per p
bagirrra123 [75]
Label each nut with a variable, c = cashews, p = peanuts.....
for a 10-pound mix, you will need c + p = 10
the price for 10-pounds would become 3.29 x 10 = 32.90 

You will need an unknown amount of cashews at 5.60/lb and an unknown amount of peanuts at 2.30/lbs to get your full 10 pounds valued at 32.90
5.60c + 2.30p = 32.90 

Now you 2 have a system of 2 equations and 2 unknowns
c + p = 105.6c + 2.3p = 32.9utilize substitution to solve:p = 10-c
5.6 c + 2.3 (10-c) = 32.9
solve for c then substitute back into c + p = 10 to solve for P

Hope this helps!
3 0
3 years ago
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