Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
1 kilometre is 0.621 mile
I would add like terms, meaning subtract 6.4 from both sides.
3.5n = 36.1
• P is the principal amount, $3000.00.
• r is the interest rate, 6% per year, or in decimal form, 6/100=0.06.
• t is the time involved, 8 years time periods.
• So, t is 8 year time periods.
To find the simple interest, we multiply 3000 × 0.06 × 8 to get that:
The interest is: $1440.00
. 6 and 10 can both be divided by 2, so your final solution is 