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Leona [35]
3 years ago
14

2 ways to distribute 18 pizzas with 24 players?

Mathematics
2 answers:
Inga [223]3 years ago
8 0
18÷24=0.75th of a pizza
andriy [413]3 years ago
8 0
Each of them can get 3/4 or 6/8
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Please solve no links i will mark brailest
Lemur [1.5K]

Answer:

oki! Mizuki here to help! 12 will be your answer!

Step-by-step explanation:

Soo... The ratio of blue to green is 4:3 right?

and there are 21 balloons!

4 + 3 is 7! So we divide 21 by 7 and get 3!

Then we multiply 3 by the number of blue balloons(aka 4) and get 12!

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PQ= 10x-2, PL= 5x-8, and LQ= 7x-12. Find LQ. Need help...
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What is the unit rate depicted in the graph?
Rina8888 [55]
Hi pupil here's your answer ::

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The unit rate depicted in the graph is must be
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3 years ago
Read 2 more answers
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
The perimeter of square F is 23 meter less than the perimeter of square G.
Zigmanuir [339]

Answer: b

hope this helps

7 0
3 years ago
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