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vfiekz [6]
3 years ago
12

What is the 24th term if the arithmetic sequence where a1 = 8 and a9 = 56

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer:

a_{24} = 146

Step-by-step explanation:

a1 = 8

a9 = 56

Using formula for finding nth term of arithmeric sequence

a_{n} =a_{1} + (n-1)d

We have to find 24th term, therefore n = 24

a_{1} is the first term but we are missing d

d is the difference between the two consecutive terms, lets calculate it first


a9 = 56

Using the above given formula for finding d

put n = 9,  a9= 56

a_{9} =a_{1}+ (9-1)d

56 = 8 + 8d

8d = 48

d = 6


Getting back to main part of finding 24th term

n = 24, d = 6, a1 = 8

put values in nth term formula

a_{n} =a_{1}+ (n-1)d

a_{24} = 8 + (24-1)6

a_{24} = 8 + 138

a_{24} = 146



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