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mr_godi [17]
3 years ago
6

What are the values of a and b? (500 + ax)(50 - bx) pls hurry

Mathematics
1 answer:
gregori [183]3 years ago
3 0

Answer:

Step-by-step explanation:

Perform the indicated multiplication first:

25000 - 500bx + 50ax - abx²

It would seem that this should be part of an equation, and that the other part is missing; without another part, there's no way to determine the values of a and b.  Please ensure you have copied this problem down completely.

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When the target number is rounded to the nearest million, the millions digit is 1.
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185445

Step-by-step explanation:

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A company that produces ribbon has found that the marginal cost of producing x yards of fancy ribbon is given by Upper C prime l
denis-greek [22]

Answer:

Step-by-step explanation:

Given:

C_{(x)}=-0.00001x^{2}-0.02x+49

for x≤1400; N = 5

So, Δx = \frac{1400-0}{5} =280\\\\\int\limits^{1400}_0 {C(x)} \, dx=∑C(a + nΔx).Δx

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=280[165.48]

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What is the difference between AD and BC​
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Which shows one way to determine the factors of x3 11x2 – 3x – 33 by grouping? x2(x 11) 3(x – 11) x2(x – 11) – 3(x – 11) x2(x 11
Aloiza [94]

The one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The steps involved in the factorization are;

1. For each pair of parentheses, we create a common factor.

2. We use x2 as a common factor for the first parenthesis.

3. We use common factor 3 for the second parenthesis.

x^3  + 11x^2 - 3x -33 \\\\ x^2(x+11)-3(x+11)_

We will find the final solution as x^2(x+11)-3(x+11)_.

Hence the one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

To learn more about the factorization refer to the link;

brainly.com/question/24182713

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2 years ago
The frequency table below displays 17 students'
vazorg [7]
Yes, because the data can be displayed by a relative frequency compared with the whole.
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