The probability of the union of two events is the sum of their probability, minus the probability of their interserction:
If we plug the known values into this formula, we have
From which we can deduce
So, the probability of 
is a bit less than 
, we have to take away all events that belong to B as well:
Answer:
choice 1) 37.68 inches
Step-by-step explanation:
3.14 x 12 = 37.68
Answer:
The rate at which the distance between the two cars is increasing is 30 mi/h
Step-by-step explanation:
Given;
speed of the first car, v₁ = 24 mi/h
speed of the second car, v₂ = 18 mi/h
Two hours later, the position of the cars is calculated as;
position of the first car, d₁ = 24 mi/h x 2 h = 48 mi
position of the second car, d₂ = 18 mi/h x 2 h = 36 mi
The displacement of the two car is calculated as;
displacement, d² = 48² + 36²
d² = 3600
d = √3600
d = 60 mi
The rate at which this displacement is changing = (60 mi) / (2h)
= 30 mi/h
