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ale4655 [162]
3 years ago
14

The coordinates of the vertices of a regular polygon are given. Find the area of the polygon to the nearest tenth.

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0

Answer:

The area is equal to 8\ units^{2}

Step-by-step explanation:

we have

A(0, 0), B(2, -2), C(0, -4), D(-2, -2)

Plot the figure

The figure is a square (remember that a regular polygon has equal sides and equal internal angles)

see the attached figure

The area of the square is

A=AB^{2}

<u><em>Find the distance AB</em></u>

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

AB=\sqrt{(-2-0)^{2}+(2-0)^{2}}

AB=\sqrt{(-2)^{2}+(2)^{2}}

AB=\sqrt{8}

AB=2\sqrt{2}\ units

<u><em>Find the area of the square</em></u>

A=(2\sqrt{2})^{2}

A=8\ units^{2}

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2 years ago
Evaluate the line integral, where c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
Arada [10]

The value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)

x(t) = (1-t)0 + t×2 = 2t  

y(t) = (1-t)0 + t×3 = 3t

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Finding its derivative;

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The line integral is given by:

\rm \int\limits_C {xe^{yz}} \, ds = \int\limits^1_0 {2te^{12t^2}} \, \sqrt{2^2+3^2+4^2} dt

 

\rm ds = \sqrt{2^2+3^2+4^2} dt

After solving the integration over the limit 0 to 1, we will get;

\rm \int\limits_C {xe^{yz}} \, ds = \dfrac{\sqrt{29}}{12}  (e^{12}-1)   or

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Thus, the value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

Learn more about integration here:

brainly.com/question/18125359

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Step-by-step explanation:

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