Answer:
The first plant demonstrate stunt growth. The second one demonstrate rapid growth
Explanation:
The first one lacks proper care and is not exposed to sunlight. The second one is the opposite of the first one
Answer:
The mouse and shrew bones were common to all three owls so they were not useful in identifying environments. The gopher bones were unique to the great grey owl of Alaska. Gophers are rodents that are successful in areas with soft soil and lots of grass, so the gopher and this owl would be found in the meadows and evergreen forests of Alaska. The bat was unique to the barking owl of Australia. The bat would be found in woodland habitats where there are many trees the bat can hang from. The gull bones were unique to the short-eared owl of Cuba. Gulls are wetland birds, so the gull and this owl would be found in marshes and coastal areas.
Answer:
1.2 mL
Explanation:
<em>This is a problem of simple dilution. The dilution principle simply agrees that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Recall that: number of moles = mass/molar mass or molarity x volume.
Hence, for the dilution principle:
initial molarity x initial volume = final molarity x final volume.
In this case, initial molarity of NaOH = 1 M, initial volume = ?, final molarity = 0.1 M, final volume = 12.0 mL.
Initial volume = final molarity x final volume/initial molarity
= 0.1 x 12/1 = 1.2 mL
It thus means that 1.2 mL of 1 M NaOH would be taken and then diluted up to 12.0 mL mark by the addition of distilled water in order to produce 12.0 mL, 0.10 M NaOH solution.
Answer:
The problem needs to be stated at the beginning of the process.
Explanation:
Conclusions are formed at the end.
It is VERY important to form a hypothesis.
And data can be analyzed many many ways.
