An animal that eats only plants is called a herbivore because it comes from herbs
Answer:
b. Detachment of a separate hybridized probe molecule from the template DNA
Explanation:
Molecular beacons are a type of genetic probe that enables the hybridization of oligonucleotides. These molecules have a flourishing component that binds to a nucleotide sequence and allows the identification of this nucleotide sequence in DNA or RNA without the release of radioactivity. For the use of these molecular beacons to be possible, one needs complementarity between the model DNA and the probe sequence, illumination of the hybridized beacon to detect fluorescence and proximity-based quenching of the fluorophore prior to beacon hybridization.
Answer:
B) How often a disease occurs in a particular area or group of people
Explanation:
Epidemiologists study diseases in many different situations. Their main goal is to prevent diseases by using this information to plan and evaluate strategies.
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~Silver
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
Answer:
There was no oxygen in the flask.
Explanation:
Anaerobic organism do not need oxygen!!
