Question

A beaker is filled 60 cm high with this liquid. What is the total pressure at the bottom of the beaker? (1 atm =1.013 x 105 Pa) Assume that the experiment was conducted at sea level.

Answer 1

Answer:

Total pressure =1.01*10^5 Pa

Explanation:

given data:

atmospheric pressure = 1.013 *10^5 Pa\

height of water column = 60 cm

Total pressure will be sum of atmospheric pressure and pressure due to water column

P =  Atmospheric pressure + pressure due to water column

pressure due to water =$\rho*g*h$

\rho of water  = 1420 kg/m^{3}

height of water column = 60 cm =0.60 m

$Total pressure =1.013*10^{5}Pa + 1420*9.81*.60$

Total pressure  = 109649.6 Pa = 1.10*10^5 Pa

Total pressure =1.01*10^5 Pa