A beaker is filled 60 cm high with this liquid. What is the total pressure at the bottom of the beaker? (1 atm =1.013 x 105 Pa)
1 answer:
Answer:
Total pressure =1.01*10^5 Pa
Explanation:
given data:
atmospheric pressure = 1.013 *10^5 Pa\
height of water column = 60 cm
Total pressure will be sum of atmospheric pressure and pressure due to water column
P = Atmospheric pressure + pressure due to water column
pressure due to water =
\rho of water = 1420 kg/m^{3}
height of water column = 60 cm =0.60 m
Total pressure = 109649.6 Pa = 1.10*10^5 Pa
Total pressure =1.01*10^5 Pa
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