<span>32 mph
First, let's calculate the location of the particle at t=1, and t=4
t=1
s = 6*t^2 + 2*t
s = 6*1^2 + 2*1
s = 6 + 2
s = 8
t = 4
s = 6*t^2 + 2*t
s = 6*4^2 + 2*4
s = 6*16 + 8
s = 96 + 8
s = 104
So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
avg_vel = (104-8)/(4-1) = 96/3 = 32
And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
The speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.
The angular momentum(L) of an electron moving in a circular path is given by the formula,
L = mvr ........(i)
We know that the radius of the path of an electron in a magnetic field is
r = mv/qB
Putting this value in equation (i),
L = mv x mv/qB
or L = (mv)^2/qB
Putting the given values in the above equation,
4 x 10^-25 = (9.1x10^-31)^2 x v^2/ 1.6 x 10^-19 x 1 x 10^-3
v comes out to be 8.88 x 10^7 m/s.
Hence, the speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.
To know more about "angular momentum", refer to the following link:
brainly.com/question/15104254?referrer=searchResults
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4200000 is your answer hope this helps
Answer: 2 m/s^2
Explain
£F=ma
net force = mass x acceleration
4N is a force acting on it
4N=(2kg) a
2kg is the mass
you divide the 2 over
and A= 2 m/s^2
Answer:
V=11.74m/s, 69.59°
Explanation:
From newtons equation of motion ,we know that
V^2 = u^2+2gh
for the rt
For the vertical component of the speed
Vy^2=V0^2+ 2gh
Vy= the final speed in the vertical axis
V0= initial speed, 0m/s
g= acceleration due to gravity 9.81m/s
h=height/distance between the eagle and the lake
Vy^2= 2*9.81*6.2
Vy =√121.644
Vy=11.02m/s
The resultant speed will be
V=(Vy^2+Vx^2)^0.5
V=(11.02^2+4.1^2)^0.5
V=137.7241^0.5
V=11.74m/s
Direction
Tan^-1(11.02/4.1)
β=69.59°
V=11.74m/s, 69.59°
Answer =11.74m/s, b°