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3 years ago

If you know the volume of a cube, how do you find its edge length?

Mathematics

1 answer:

Helga [31]3 years ago

8 0

V = (edge)^3

If you know the volume, take the CUBE ROOT on both sides to find the edge.

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Estimate 6.1 divided by 8

victus00 [196]

0.7 is your answer
:) happy to help

6 0

4 years ago

Read 2 more answers

20x^2-30=4x solve for x

ankoles [38]

Answer:

x=1.3288 or -1.1288

Step-by-step explanation:

Given $20x^{2}-30=4x$

Subtract 4x from both sides

$20x^{2}-4x-30=0$

Since we can factor out 2 from whole equation, let's factor out 2.

$2(10x^{2}-2x-15)=0$

Divide with 2 on both sides

$10x^{2}-2x-15=0$

We got the quadratic equation, we can solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}$

$x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}$

$x=\frac{2\pm\sqrt{604} }{20}$

$x=\frac{2\pm2\sqrt{151}}{20}$

$x=1.3288or-1.1288$

8 0

3 years ago

Read 2 more answers

8x^2+32x-96<img src="https://tex.z-dn.net/?f=8x%5E%7B2%7D%20%2B36x-96" id="TexFormula1" title="8x^{2} +36x-96" alt="8x^{2} +36x-

erma4kov [3.2K]

Answer:

−19282+104−96

Step-by-step explanation:

hopefully this helps, I'm not sure I'd it is correct though

4 0

3 years ago

What is the third quartile of this data set? *I NEED THE HELP ASAP* thx

diamong [38]

I think the answer is 44

7 0

3 years ago

What are the vertex and x-intercepts of the graph of the function below?

geniusboy [140]

y= x^2 - 6x-7

Vertex = -b /2a

b= -6

a= 1

-(-6)/2(1)= 3

x= 3

Use the substitution method to find y

y= (3)^2-6(3)-7

(3)(3)-18-7

9-25

y= -16

Vertex is (3, 16)

Find x- intercept (y= 0)

y= x^2 - 6x-7

(x-7)(x+1)

x-7= 0

Move -7 to the other side. Sign changes from -7 to 7

x-7+7= 0+7

x= 7

x+1= 0

Move +1 to the other side. Sign changes from +1 to -1

x+1-1= 0-1

x= -1

Answer :B. Vertex: (3, -16); Intercepts: x=-1,7

5 0

3 years ago