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2 years ago

The diagram shows the distance between my home, H. and two towns, A and B.

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

7 0

I do not know English :33333

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Bella has 6.3 kg of berries. she packs 0.35 kg of berries in each containers. then sells each container for $2.99. how much mone

katovenus [111]

Answer:

$53.82

Step-by-step explanation:

6.3 / 0.35=18

$2.99 x 18= $53.82

hope this halps :)

8 0

3 years ago

For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

4 0

3 years ago

Graph the hyperbola y^2/16-x^2/9=1. What type of transverse axis does it have?

gulaghasi [49]

<span>Center(0,0)
a^2=16
a=4
b^2=9

b=3
c^2=a^2+b^2=16+9=25
c=√25=5</span>

3 0

3 years ago

If L, M and N are midpoints of the sides of PQR, PR = 46, PQ = 40, and LN=17, find each measure

Serga [27]

Check the picture below.

let's recall that the midsegment of a triangle is the segment that's half-way to both endsides and is at the same time parallel to the 3rd side, is also half the length of the parallel side, so-called the base.

so, for example, we know L, M and N are midpoints to each segment, that means that LM is a midsegment and parallel to PR and also half the length of PR, same is true for LN and MN.

5 0

3 years ago

Plzzzzz help I don’t understand and this question is worth 23 points that’s how much I need to know how to do this and I need to

butalik [34]

You need PEMDAS
do 3·6 and then 12/6
when you subtract the product and quoetient you get 16 for the answer

6 0

3 years ago

Read 2 more answers