We are given the perimeter of isosceles trapezoid = 28 in ratio of length of bases = 5:3
We are to find the lengths of sides of the trapezoid and the diagonal that bisects the angle at the base with a longer length
The formula for the perimeter of an isosceles trapezoid is P = (1/2) (b1 + b2) h
We are given the ratio b2/ b1 = 5 /3 b2 = 5/3 b1 Substituting 28 = (1/2) (5/3 b1) h The height of the trapezoid is expressed in terms of b1 For the diagonal d² = h² + [(b2 - b1) + (b2 - b1)/2]² Express h and b2 in terms of b1 and diagonal can be expressed in terms of b1
