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2 years ago

I need to find the expression for the nth term

Mathematics

1 answer:

alex41 [277]2 years ago

3 0

2. 30, 24, 34, 28,
Pattern: Subtract 6, Add 10

3. 19, 18.75, 18.5, 18.25
Pattern: Subtract .25

4. 42, 56, 72, 90
This pattern is hard to explain...
1st number: 1 x 2 (2)
2nd number: 2 x 3 (6)
3rd number: 3 x 4 (12)
And so on.

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I need to know the amount of Iodine -131 remaining after 72 days

jenyasd209 [6]

Answer:

131 remaining after 72 days

Step-by-step explanation:

4 0

3 years ago

Math:

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago

The points plotted below are on the graph of a polynomial. Which of the following x-values best approximate roots of the polynom

Kaylis [27]

Answer:

The correct options are:

x= -1.1

x= 2.4

x = 6

Step-by-step explanation:

The roots of any polynomial can easily be determined by the graph. To find the roots from the graph, we just have to see the values of x, for which the value of whole polynomial becomes 0.

We can see in the graph that there are three points where the value of polynomial becomes 0. that are

At x= -1.1

At x= 2.4

At x = 6

Thus, these are the roots

8 0

2 years ago

If g(x)=x^2-4 find g(5)

spin [16.1K]

Put 5 instead of x
g(5)=5^2-4=21

7 0

3 years ago