The answer is $432
Multiply 400 by .08 and you get 32, which you add to the original price.
Answer:
the conditional probability that X = 1 , X = 2 and X = 3 is 0.7333 (73.33%) , 0.25 (25%) and 0.0167 (1.67%) respectively
Step-by-step explanation:
a player wins money when i>0 then defining event W= gain money , then
P(W) = p(i>0) = p(1)+p(2)+p(3)
then the conditional probability can be calculated through the theorem of Bayes
P(X=1/W)= P(X=1 ∩ W)/P(W)
where
P(X=1 ∩ W)= probability that the payout is 1 and earns money
P(X=1 / W)= probability that the payout is 1 given money was earned
then
P(X=1/W)= P(X=1 ∩ W)/P(W) = P(X=1) / P(W) = p(1) /[p(1)+p(2)+p(3)] = 11/40 /(11/40+3/32+1/160
) = 0.7333 (73.33%)
similarly
P(X=2/W)=p(2) /[p(1)+p(2)+p(3)] = 3/32 /(11/40+3/32+1/160
) = 0.25 (25%)
P(X=3/W)=p(2) /[p(1)+p(2)+p(3)] = 1/160 /(11/40+3/32+1/160
) = 0.0167 (1.67%)
Answer:
A consumer organization estimates that over a 1-year period 16% of cars will need to be repaired once, 9% will need repairs twice, and 3% will require three or more repairs..
We have the cars that do not need repair =
%
(16+9+3=28% cars need repair of some sort)
What is the probability that :
a) neither will need repair?
=> 
b) both will need repair?
=>
c) at least one car will need repair?
=> 
=> 
Answer:
5
Explanation:
1. Find a common denominator for the three fractions. A common denominator is a number all three numbers divide into evenly. The lowest common denominator for 4, 3, and 6 is 12.
2. Find the numerators. This can be done by multiplying the current numerators by however many times the old denominator goes into the new denominator.
4 goes into 12 3 times
3 goes into 12 4 times
6 goes into 12 2 times
1 x 3 = 3
2 x 4 = 8
1 x 6 = 6
So, the fractions become:

3. Add the numerators of the new fractions and keep the denominator the same.

4. Convert the improper fraction to a mixed number.

5. Finally, add the whole numbers.
1 + 4 = 5
28=9n-17
45=9n
5=n
One side is 5
One side is 11
One side is 12