Answer:
The equation of the line is y = -1.5x + 3
The y-intercept is (0,3)
The value of k is 3.
Step-by-step explanation:
y - 0 = -1.5 (x - 2)
y = -1.5x + 3
Answer:
r=3 ft
Step-by-step explanation:
it is similarity of two triangles
one
perpendicular side=10 ft
base=10/2=5 ft
second
perpendicular side=10-4=6 ft
Base r=?

Given Information:
Mean SAT score = μ = 1500
Standard deviation of SAT score = σ = 3
00
Required Information:
Minimum score in the top 10% of this test that qualifies for the scholarship = ?
Answer:

Step-by-step explanation:
What is Normal Distribution?
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
We want to find out the minimum score that qualifies for the scholarship by scoring in the top 10% of this test.

The z-score corresponding to the probability of 0.90 is 1.28 (from the z-table)

Therefore, you need to score 1884 in order to qualify for the scholarship.
How to use z-table?
Step 1:
In the z-table, find the probability value of 0.90 and note down the value of the that row which is 1.2
Step 2:
Then look up at the top of z-table and note down the value of the that column which is 0.08
Step 3:
Finally, note down the intersection of step 1 and step 2 which is 1.28
Answer:
Looks like all of your questions have been answered.
Answer:
distance = 5 units
Step-by-step explanation:
In order to solve this problem we can start by plotting the two points you were provided with (see attached picture). This will help us visualize the problem better.
Now, we need to find the distance between those two points, so in order to do so we can use the distance formula:

in this case the x's and y's are given by the given points, since they are written as ordere pairs. And ordered pairs are written in the form (x,y). So for Point C:
C=(-1,4)


and for point D
D=(2.0)


so we can now use those values in our distance formula so we get:




d=5 units.