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3 years ago

Need help bad !!!!!!!!!!!!

Mathematics

2 answers:

Sergio [31]3 years ago

6 0

Answer:

Step-by-step explanation:

Using the midpoint formula

midpoint = [ $\frac{1}{2}$ ( $x_{1}$ + $x_{2}$ ), $\frac{1}{2}$ ( $y_{1}$ + $y_{2}$ ) ]

with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (6, - 4)

midpoint = [ $\frac{1}{2}$ (- 2 + 6), $\frac{1}{2}$ (4 - 4) ]

= (2, 0) → B

Nonamiya [84]3 years ago

4 0

There are 2 order pairs there (6,-4),(-2,4)
find the midpoint using the formula

(x1+x2)/2 , (y1+y2)/2
x=6 and -2
y=-4 and 4

(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A

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If a loan of 1,500 at 4% is paid off in 90 days what is the interest

slega [8]

Answer:

Compound interest =$14.58

Simple Interest=$14.79

Step-by-step explanation:

Let's assume the interest rate charged on the loan was simple in nature.

-Simple interest is calculated using the formula:

$I=PRT,\\\\=1500\times 0.04\times \frac{90}{365}\\\\=14.79$

Hence, the simple interest on the loan was $14.79

#If the interest is compound in nature with just one compounding per year:

$A=P(1+i)^n\\\\I=A-P\\\\I=1500(1.04)^{90/365}-1500\\\\=14.58$

Hence, the compound interest charged on the loan is $14.58

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3 years ago

What are both of these shaded as?

Sedaia [141]

Answer:

1 whole and 15/100= <em><u>1.15</u></em>

Step-by-step explanation:

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4 0

3 years ago

Whaich calculation and answer show how to convert 3/12 to a decimal

Zolol [24]

Answer:

0.25

Step-by-step explanation:

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7 0

3 years ago

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Vikentia [17]

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3 years ago

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

3 years ago

Need help bad !!!!!!!!!!!!​

Need help bad !!!!!!!!!!!!