Need help bad !!!!!!!!!!!!

Mathematics

2 answers:

Sergio [31]3 years ago

6 0

Answer:

Step-by-step explanation:

Using the midpoint formula

midpoint = [ $\frac{1}{2}$ ( $x_{1}$ + $x_{2}$ ), $\frac{1}{2}$ ( $y_{1}$ + $y_{2}$ ) ]

with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (6, - 4)

midpoint = [ $\frac{1}{2}$ (- 2 + 6), $\frac{1}{2}$ (4 - 4) ]

= (2, 0) → B

Nonamiya [84]3 years ago

4 0

There are 2 order pairs there (6,-4),(-2,4)
find the midpoint using the formula

(x1+x2)/2 , (y1+y2)/2
x=6 and -2
y=-4 and 4

(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A

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PLEASE HELP

sweet [91]

Answer:

a) $2 + 3 + 5 + 6 = 16$

b) $8a + b-9$

c) $8a - 28b + 15c$

Step-by-step explanation:

We are given the following in the question:

1. Equivalent expression

$2 + 3 + 5 + 6$

Since all the terms are like terms, we can write,

$2 + 3 + 5 + 6 = 16$

2. Sum of given expression

$(8a - 2b - 4) \text{ and } (3b - 5)\\ (8a - 2b - 4) + (3b -5)\\= 8a -2b -4 + 3b -5\\\text{Collecting the like terms}\\8a + (-2b+3b) + (-4-5)\\= 8a + b-9$