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3 years ago

HELP ASAP!!! PLEASE CHECK ALL OF THEM!

Mathematics

1 answer:

pochemuha3 years ago

8 0

Answer:

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

1-4

= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

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Each of 3 bags contains x pencils. Tyler adds 2 more pencils to each bag. Altogether, the gift bags contain 12 pencils.

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5 0

3 years ago

-3/v=-6 simply as much as possible

Aleksandr [31]

Hey!

In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

Original Equation :
$\frac{-3}{v} = -6$

New Equation {Added Multiply Both Sides by V} :
$\frac{-3}{v} v=-6v$

Solution {New Equation Solved} :
$-3 = -6v$

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

Old Equation :
$-3 = -6v$

New Equation {Switched} :
$-6v=-3$

Now we'll divide both sides by v to get v on its own.

Old Equation :
$-6v = -3$

New Equation {Added Divide Both Sides by V} :
$\frac{-6v}{v} = \frac{-3}{v}$

Solution {New Equation Solved} :
$v = \frac{1}{2}$

So, this means that in the equation $\frac{-3}{v} =-6$ , $v = \frac{1}{2}$ .

Hope this helps!

- Lindsey Frazier ♥

3 0

3 years ago

If f(x) = 5x – 2 and g(x) = 2x + 1, find (f- g)(x).

GalinKa [24]

Answer:

la respuesta es A. 3x - 3

7 0

3 years ago

Write an expression that is equivalent to 3/5 (3y+15) 3/5y +9, 3/5y+15, 9/5y+9, 9/5y + 15?

NISA [10]

Given the expression

$\frac{3}{5} (3y+15)$

The expression that is equivalent to the given expression is given by:

$\frac{3}{5} (3y+15)= \frac{9}{5} y+ \frac{3}{5} (15)= \frac{9}{5} y+9$