Suppose for some value of x the solution to the equation 2.5(y−x)=0 is y = 6. What must be true about x?

Mathematics

1 answer:

Varvara68 [4.7K]2 years ago

7 0

Step-by-step explanation:

In this case, you input the value of y (y = 6) into the equation ( 2.5(y-x)= 0)

2.5(6-x) = 0

Open the bracket,

(2.5×6)-2.5x= 0

Collect like terms.

2.5x= 2.5×6

Divide both sides by the coefficient of x (2.5)

x = 6

So,

x= 6 is true.

Substituting 6 for x in the equation,

2.5(6-6)= 0

2.5•0 = 0

0= 0

Which is also true.

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