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3 years ago

0.5, 3/16, 0.75, 5/48 least to greatest

1 answer:

7 0

An easy way for me to do this is to either make all of the fractions into decimals or all the decimals into fractions, whatever you prefer. I prefer fractions, but for typing reasons I’m going to make them all decimals. Making 5/48 into a decimal you divide 5 by 48 and get 0.104... and divide 3 by 16 and get 0.1875. Then from there, look at whatever tenths place number is the least (the number after the decimal). Two of them have one, so moving onto the next number, 8>0, which means 0.104 is less then 0.1875. Then 5<7. So from least to greatest, 5/48 (0.104), 3/16 (0.1875), 0.5, 0.75.
Good Luck!

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What is the relationship between the conversion factors used in Part A of Model 2? Whatabout the conversion factors used in Part

Lelu [443]

Given:

The conversions from meter to inches and inches to meter are shown in part A of model 2.

The conversions from liters to quarts and quarts to liters are shown in part B of model 2.

Required:

To find the relationship between the conversion factors used in Part A of Model 2.

To find the relationship in the the conversion factors used in Part B of Model 2.

Explanation:

We have given that 1 meter = 39.4 inches.

Thus, from the calculations shown in part A of model 2, we can conclude that the quantity from meters to inches is converted as:

$1.5\times39.4=59$

Thus, 1.5 m =59 inches.

Also, the quantity from inches to meters is converted as:

$\frac{59}{39.4}=1.5$

Hence, 59 in = 1.5 m.

Next,

We have 1 L = 1.06 qt.

Thus, from the calculations shown in part B of model 2, we can conclude that the quantity from quarts to liters is converted as:

$\frac{186}{1.06}=175$

Thus, 186 quarts = 175 L.

Also, the quantity from liters to quarts is converted as:

$175\times1.06=186$

Hence, 175 L = 186 qt.

Final Answer:

We conclude that:

While converting from meters to inches, we multiply the quantity 1.5 by the equality quantity given.

While converting from incehs to meters, we divide the quantity 59 by the equality quantity given.

Also, While converting from quarts to liters, we divide the quntity 186 by the equality quantity given.

While converting from liters to quarts, we multiply the quntity 175 by the equality quantity given.

6 0

9 months ago

2w+2l=24 what is the value of l

valentinak56 [21]

If the question is 2w+2L=24 than the answer is 6-w=L
but if the question is 2w+21=24 the answer is w=3/2

3 0

3 years ago

What is 47/20 as a decimal

Whitepunk [10]

$x=decimal
 \\ 47 \ divided \ by \ 20 \ is \ 2.35
 \\ x=2.35
 \\$

5 0

3 years ago

Read 2 more answers

What is the unit rate of 115miles in 2hours

maksim [4K]

You would divide miles to hours amd get 57.5

5 0

3 years ago

Read 2 more answers

Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|

Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0

2 years ago