In an installment loan, a lender loans a borrower a principal amount P, on which the borrower will pay a yearly interest rate of i (as a fraction, e.g. a rate of 6% would correspond to i=0.06) for n years. The borrower pays a fixed amount M to the lender q times per year. At the end of the n years, the last payment by the borrower pays off the loan.
After k payments, the amount A still owed is
<span>A = P(1+[i/q])k - Mq([1+(i/q)]k-1)/i,
= (P-Mq/i)(1+[i/q])k + Mq/i.
</span>The amount of the fixed payment is determined by<span>M = Pi/[q(1-[1+(i/q)]-nq)].
</span>The amount of principal that can be paid off in n years is<span>P = M(1-[1+(i/q)]-nq)q/i.
</span>The number of years needed to pay off the loan isn = -log(1-[Pi/(Mq)])/(q log[1+(i/q)]).
The total amount paid by the borrower is Mnq, and the total amount of interest paid is<span>I = Mnq - P.</span>
Separate into two groups
y^3(5y+4) + 5(5y+4)
(y^3 + 5)(5y + 4)
Answer:
Equivalent ratios
20 = 40 = 60 = 80 and so on....
15 = 30 = 45 = 60 and so on.....
Both include 60
6 ,12 ,18, 24, 30 ,36 ,42, 48,
She will keep adding by 6
Answer:
60
Step-by-step explanation:
40+ 20
60
this is your answer
