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morpeh [17]
3 years ago
6

Determine whether the given procedure results in a binomial distribution​ (or a distribution that can be treated as​ binomial).

If the procedure is not​ binomial, identify at least one requirement that is not satisfied. The YSORT method of gender​ selection, developed by the Genetics​ & IVF​ Institute, was designed to increase the likelihood that a baby will be a boy. When 120 couples use the YSORT method and give birth to 120 ​babies, the genders of the babies are recorded.
Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

The procedure results in a binomial distribution

Step-by-step explanation:

If all 120 couples used the YSORT method, it is fair to assume that the probability of a baby being a boy or a girl are constant through all trials (120 couples). Assuming 120 randomly selected couples, there is a fixed number of independent trials. Finally, since the babies can only be a boy or a girl, the binary condition is satisfied and thus, the distribution is binomial

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Q4.
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The coding of the statistic is used to make it easier to work with the large sunshine data set

  • The mean of the sunshine is 3.05\overline 6
  • The standard deviation is approximately  <u>18.184</u>

<u />

Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

Mean, \ \overline x = \dfrac{\sum x_i}{n}

The mean of the daily total sunshine is therefore;

Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6

s = \dfrac{x}{10 } - \dfrac{1}{10}

  • E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}

E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6

  • The mean ≈ 3.05\overline 6

Alternatively

,The \ mean \  of \  the \  daily  \ total  \ sunshine,  \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6

The mean of the daily total sunshine, \overline s ≈3.05\overline 6

  • Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)

Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)

Therefore;

Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537

Therefore;

  • s = \sqrt{330.6537} \approx 18.184

The standard deviation, s_s ≈ <u>18.184</u>

Learn more about coding of statistic data here:

brainly.com/question/14837870

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