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daser333 [38]
3 years ago
10

A soccer field is a rectangle 48 meters wide and 55 meters long. The coach asks players to run from one corner to the corner dia

gonally across. What is this distance?
Mathematics
1 answer:
Sindrei [870]3 years ago
5 0

Answer:

Distance = 73 m

Step-by-step explanation:

Given that,

The length of a rectangle = 48 m

The width of a rectangle = 55 m

We need to find the diagonal distance. We can use the Pythagoras theorem to find it.

d^2=48^2+55^2\\\\d=\sqrt{5329}\\\\d=73\ m

So, the required distance is equal to 73 m.

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If I can paint a wall in 20 min and my friend can paint a wall in 30 min. How many minutes would it take for us to paint a wall
ra1l [238]

Answer: 12\ \text{min}

Step-by-step explanation:

Given

It takes 20 min and 30 min for  a person and his friend to paint a wall individually  i.e.

In 1 min they cover \frac{1}{20} part and \frac{1}{30} part of wall respectively.

If the work together, 1 minute work is

\Rightarrow \dfrac{1}{20}+\dfrac{1}{30}\\\\\Rightarrow \dfrac{3+2}{60}\\\\\Rightarrow \dfrac{5}{60}

Time required will be reciprocal of it

\Rightarrow \dfrac{60}{5}=12\ \text{min}

3 0
3 years ago
Can someone please help me with these questions!! Thanks,
fiasKO [112]

6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1

6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)

6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)

6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²

8 0
3 years ago
Can someone help me with these?​
Jet001 [13]
48 is the correct answer because your going to only do the square
4 0
3 years ago
Read 2 more answers
9.2 HW Central Angles, Arc Measures, & Arc Length
kap26 [50]

Answer:

I can help you with this, i just need the actual questions.

Step-by-step explanation:

5 0
3 years ago
A hospital prepares a 100mg supply of technetium-99m which has a half-life of 6 hours. what is the decay factor?
SashulF [63]
For a half- life, the formula is
A(t) = A0(0.5)^( t / t_0.5)
where A(t) is the amount of substance at time t
A0 is the initial amount of subtance
t_0.5 is the time it will reduce its amount to half
t is the time

substitute the given to the formula
A(t) = 100(0.5)^( t/6 )
so the decay factor is 0.5^( t/6 )
6 0
3 years ago
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