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blsea [12.9K]
3 years ago
11

Help!!!!! Pleaseee I don’t understand

Mathematics
1 answer:
Neko [114]3 years ago
8 0

Answer:

  • Question 22: x = 3
  • Question 23: AB = 10
  • Question 24: BD = 14
  • Question 25: CE = 17

Concept:

Here, we need to know the idea of the segment addition postulate.

The <u>Segment Addition Postulate </u>states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation <u>AB + BC = AC</u>.

If you are still confused, you may tell me or refer to the attachment below for a graphical explanation.

Solve:

<u>Question 22. If AC = 16, what is x?</u>

<em>Given information</em>

AC = 16

AB = x + 7

BC = 2x

<em>Given expression deducted from the segment addition postulate</em>

AB + BC = AC

<em>Substitute values into the expression</em>

x + 7 + 2x = 16

<em>Combine like terms</em>

x + 2x + 7 = 16

3x + 7 = 16

<em>Subtract 7 on both sides</em>

3x + 7 - 7 = 16 - 7

3x = 9

<em>Divide 3 on both sides</em>

3x / 3 = 9 / 3

\boxed {x=3}

<u>Question 23. What is AB?</u>

<em>Given information</em>

x = 3

<em>Given expression deducted from the segment addition postulate</em>

AB = x + 7

<em>Substitute values into the expression</em>

AB = (3) + 7

\boxed {AB=10}

<u>Question 24. What is BD?</u>

<em>Given information</em>

BC = 2x

CD = 3x - 1

x = 3

<em>Given expression deducted from the segment addition postulate</em>

BD = BC + CD

<em>Substitute values into the expression</em>

BD = 2x + 3x - 1

BD = 2(3) + 3(3) - 1

BD = 6 + 9 - 1

BD = 15 - 1

\boxed {BD=14}

<u>Question 25. What is CE?</u>

<em>Given information</em>

CD = 3x - 1

DE = 2x + 3

x = 3

<em>Given expression deducted from the segment addition postulate</em>

CE = CD + DE

<em>Substitute values into the expression</em>

CE = 3x - 1 + 2x + 3

CE = 3(3) - 1 + 2(3) + 3

CE = 9 - 1 + 6 + 3

CE = 8 + 6 + 3

CE = 14 + 3

\boxed {CE=17}

Hope this helps!! :)

Please let me know if you have any questions

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