F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
The answer is a..................................
The answer is C. 6+3 x (-5)
Answer:
5v^2x + 4
Step-by-step explanation:
I'm not sure but i hope this help's
Answer: 17
Step by step : 146+2x=180
2x=34
X=17
