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BlackZzzverrR [31]
3 years ago
9

What is the product? (4x)(-3x^8)(-7x^3) 0 -84x^12 o -84x^24 O 84x^12 O 84x^24

Mathematics
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer:

84 {x}^{12}  \:

Option C

Step-by-step explanation:

(4x)( - 3 {x}^{8} )( - 7 {x}^{3} )

(4x)(21 {x}^{8 + 3} )

84 {x}^{1 + 11}

84 {x}^{12}

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Integers from least to greatest 11 -3.5 -10 6 -12<br> HELPPPP FAST PLEASE
Aliun [14]

Answer:-12, -10, -3.5, 6, 11

Step-by-step explanation:

7 0
2 years ago
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A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+
Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

C(x) = 4 + 0.10(x-70)

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

C(x) \geq 7

4 + 0.10(x - 70) \geq 7

4 + 0.10x - 7 \geq 7

0.10x \geq 10

x \geq \frac{10}{0.1}

x \geq 100

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

C(x) \leq 8

4 + 0.10(x - 70) \leq 8

4 + 0.10x - 7 \leq 8

0.10x \leq 11

x \leq \frac{11}{0.1}

x \leq 110

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0
3 years ago
A suspicious monkey offers you and your classmates fruit to eat. As you consider eating the fruit he tells you that 60 out of 12
Georgia [21]

Answer

4.84%

Step-by-step explanation:

trust me

3 0
2 years ago
Write the equation in exponential form log2 128=7
zubka84 [21]
The answer is <span>2^7 = 128<span>

</span></span>
6 0
3 years ago
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Use a double angle or half angle identity to find the exact value of each expression
inna [77]

<em>θ</em> is given to be in the fourth quadrant (270° < <em>θ</em> < 360°) for which sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. This means

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1   ==>   sin(<em>θ</em>) = -√[1 - cos²(<em>θ</em>)] = -3/5

Now recall the double angle identity for sine:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

==>   sin(2<em>θ</em>) = 2 (-3/5) (4/5) = -24/25

4 0
3 years ago
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