I think it might be 30 but I don’t know
Answer:
The points are sqrt(164) or 2sqrt(41) units apart.
Explanation:
You didn't provide the options in your question. But to find the distance, you need to use the distance formula.
d=sqrt((y2-y1)^2 + (x2-x1)^2)
d is the distance, and (x1, y1) and (x2, y2) are the points.
Use point J (-4,-6) for (x1,y1) and point K (4,4) for (x2, y2).
d=sqrt((4-(-6))^2 + (4-(-4))^2)
=sqrt(10^2 + 8^2)
=sqrt(100+64)
=sqrt(164)=2sqrt(41)
You can compare this to the answer options and find the closest. Hope I could help! :)
Answer:
0% probability that a customer will be exactly 7.50 minutes in the record store.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
The probability of finding a value between c and d is:
The probability of finding a value above x is:
The uniform distribution is a continuous distribution, which means that the probability of an exact outcome is zero.
Uniformly distributed between 3 and 12 minutes.
This means that 
What is the probability that a customer will be exactly 7.50 minutes in the record store?
Continuous distribution, so:
0% probability that a customer will be exactly 7.50 minutes in the record store.
<h3>Answer: 0.47178 Step-by-step explanation:
Find the probability for each p(X=x) up to 5 using the equation: (x-1)C(r-1)*p^r * q^x-r,
where x is number of days, p = .3 (prob of rain). q=.7 (prob of not rain), and r=2 (second day of rain). also C means choose.
So p(X=1) = 0
p(X=2) = 1C1 * .3^2 * .7^0 = .09
P(X=3) = 2C1 * .3^2 * .7^1 = .126
P(X=4) = 3C1 * .3^2 * .7^2 = .1323
P(X=5) = 4C1 * .3^2 * .7^3 = .12348
Then add all of them up
0+.09+.126+.1323+.12348 = .47178</h3>
Would you like a full explanation or is it better for me just to plug it all in to my graphing calculator to get quick answers
