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4 years ago

15

45 POINTS!!!! I need help with number 1, I don’t understand it, can someone explain pls :)

1 answer:

xxMikexx [17]4 years ago

7 0

Answer:

Recognize and use measures of center and measures of variation to describe data. Recognize that a measure of center for a numerical data set summarizes all of its values with a single number, while a measure of variation describes how its values vary with a single number.

Step-by-step explanation:

look at the examples below for more help, good luck!!

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Which table has a constant of proportionality of 8/5

Fudgin [204]

Sorry there’s no info here

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3 years ago

A 21 foot tower must be secured with a wire anchored 7 feet from the base of the tower. What angle will the wire make with the g

weqwewe [10]

Answer:

30

Step-by-step explanation:

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4 years ago

How do you know what to split 26 into ?

madam [21]

Answer:

see explanation

Step-by-step explanation:

Assuming you are factoring the expression

Given

4y² + 26y + 30 ← factor out 2 from each term

= 2(2y² + 13y + 15) ← factor the quadratic

Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term.

product = 2 × 15 = 30 and sum = 13

the factors are 10 and 3

Use these factors to split the y- term

2y² + 10y + 3y + 15 ( factor the first/second and third/fourth terms )

= 2y(y + 5) + 3(y + 5) ← factor out (y + 5) from each term

= (y + 5)(2y + 3)

Thus

4y² + 26y + 30

= 2(y + 5)(2y + 3)

5 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Divide. Write the quotient in the lowest terms.

oee [108]

Answer:

$12/1\frac{1}{5}$ $= 10$

8 0

3 years ago

Read 2 more answers